keys = ["azc", "dwf", "gti", "jql", "mon", "pkr", "shu", "vex", "yb"]
password = "awdsdasd"
time = 0
before_word = '+'         # 前一位密码，初始用+替代，以免误判
for word in password:
    for key in keys:
        if word in key:
            time += key.index(word)+1     # 密码在这个键盘的下标+1（下标0开始）
            if before_word in key:       # 前一位密码是否和当前密码在同一个键位上，是就+2
                time += 2
            before_word = key             
            break
print(time)

没用啥算法，效率可能比较低