Python 给出 Python 中变量名的列表,如何创建一个具有变量名称作为键的字典 (到变量的值)
name = 'foo'
zip1 = 123
message = dict([(x, locals()[x]) for x in ['name', 'zip1']])
print(message)
console：
Traceback (most recent call last):
File "C:/Users/Administrator/PycharmProjects/YangoManagementPlatformWebTest/common/mysql.py", line 103, in <module>
message = dict([(x, locals()[x]) for x in ['name', 'zip1']])
File "C:/Users/Administrator/PycharmProjects/YangoManagementPlatformWebTest/common/mysql.py", line 103, in <listcomp>
message = dict([(x, locals()[x]) for x in ['name', 'zip1']])
KeyError: 'name'
请问问题出在哪里呢？
name = 'foo'
zip1 = 123
temp_dic = locals()
message = dict([(x, temp_dic[x]) for x in ['name', 'zip1']])
print(message)
locals() 是获取局部变量 ，而列表生成式迭代时候类似创建了个函数，那么你在这个函数空间内，locals() 就取不到 name 和 zip
例如：
def my_range():
print(locals())
my_range()
>> {}
1.在列表生成式外面用变量赋值
2.使用 globals()
