有一个字符串,字符串中包含三个变量,而三个变量,每个变量又有多个取值,怎么全遍历一遍?
比如
str1 = "第一个变量{var1},第二个变量{var2},第三个变量{var3}"
var1=["1","2","3"]
var2=["4","5","6","7"]
var3=["8","9","10"]
str1 的遍历应该有 3*4*3 种结果
请问怎么简单点搞出来结果?
import itertools
if __name__ == '__main__':
str1 = '第一个变量{},第二个变量{},第三个变量{}'
var1 = ['1', '2', '3']
var2 = ['4', '5', '6', '7']
var3 = ['8', '9', '10']
for item in itertools.product(var1, var2, var3):
print(str1.format(item[0], item[1], item[2]))
var1=["1","2","3"]
var2=["4","5","6","7"]
var3=["8","9","10"]
s = ((x,y,z) for x in var1 for y in var2 for z in var3)
count = 0
for i in s:
count+=1
print(i)
print(count)
for n in (var1+var2+var3) :
print n
arrow
回复
import copy
a=["1","2","3"]
b=["4","5","6","7"]
c=["10","8","9"]
def insert( sum, values ):
if sum == []:
for value in values:
sum.append( [value] )
return
tmp = copy.deepcopy(sum)
for item in tmp:
for value in values:
sum.append( item + [value] )
sum.remove( item )
if __name__ == "__main__":
sum = []
for values in [a,b,c]:
insert( sum, values )
for i in sum:
print(i)
结果:
['1', '4', '10']
['1', '4', '8']
['1', '4', '9']
['1', '5', '10']
['1', '5', '8']
['1', '5', '9']
['1', '6', '10']
['1', '6', '8']
['1', '6', '9']
['1', '7', '10']
['1', '7', '8']
['1', '7', '9']
['2', '4', '10']
['2', '4', '8']
['2', '4', '9']
['2', '5', '10']
['2', '5', '8']
['2', '5', '9']
['2', '6', '10']
['2', '6', '8']
['2', '6', '9']
['2', '7', '10']
['2', '7', '8']
['2', '7', '9']
['3', '4', '10']
['3', '4', '8']
['3', '4', '9']
['3', '5', '10']
['3', '5', '8']
['3', '5', '9']
['3', '6', '10']
['3', '6', '8']
['3', '6', '9']
['3', '7', '10']
['3', '7', '8']
['3', '7', '9']
当时我是这么写的,感觉很不 pythonic
哈哈哈,又学到一招